我想创建一个个人资料页面并显示登录人员的评论。以及对其评论的回应。

像这样：

Post title

注释（按登录用户）

--->对其评论的回应（回复）

有什么办法吗？

EDIT:

这就是我现在得到的。我在我拥有的页面上使用一个短代码来获取登录者的评论。

What I want to get is also the responses for each comment made by this logged in user.

<?php
/*
Plugin Name: Show Recent Comments by a particular user
Plugin URI: http://blog.ashfame.com/?p=876
Description: Provides a shortcode which you can use to show recent comments by a particular user
Author: Ashfame
Author URI: http://blog.ashfame.com/
License: GPL
Usage: 
*/

add_shortcode ( \'show_recent_comments\', \'show_recent_comments_handler\' );

function show_recent_comments_handler( $atts, $content = null )
{
    extract( shortcode_atts( array( 
        "count" => 10,
        "pretty_permalink" => 0
        ), $atts ));

    $output = \'\'; // this holds the output

    if ( is_user_logged_in() )
    {
        global $current_user;
        get_currentuserinfo();

        $args = array(
            \'user_id\' => $current_user->ID,
            \'number\' => $count, // how many comments to retrieve
            \'status\' => \'approve\'
            );

        $comments = get_comments( $args );
        if ( $comments )
        {
            $output.= "<ul>\\n";
            foreach ( $comments as $c )
            {
            $output.= \'<li>\';
            if ( $pretty_permalink ) // uses a lot more queries (not recommended)
                $output.= \'<a href="\'.get_comment_link( $c->comment_ID ).\'">\';
            else
                $output.= \'<a href="\'.get_settings(\'siteurl\').\'/?p=\'.$c->comment_post_ID.\'#comment-\'.$c->comment_ID.\'">\';           
            $output.= $c->comment_content;
            $output.= \'</a>\';
            $output.= "</li>\\n";
            }
            $output.= \'</ul>\';
        }
    }
    else
    {
        $output.= "<h2>You should be logged in to see your comments. Make sense?</h2>";
        $output.= \'<h2><a href="\'.get_settings(\'siteurl\').\'/wp-login.php?redirect_to=\'.get_permalink().\'">Login Now &rarr;</a></h2>\';
    }
    return $output;
}
?>